![]() ![]() ![]() These have been purposely designed to be as difficult as possible and require extreme creativity and understanding of tactical themes to solve. Do not feel that you are an inadequate player by any means if you are unable to solve these puzzles. In this blog I going to show you eight very difficult "Checkmate in Two" puzzles that will stump even the most seasoned of chess player. There is great satisfaction of finding the solutions especially when the composer hides it so well. What at first seems like a very trivial checkmate puzzle that the average chess player can solve, ends up becoming a 20-minute slog of brute force calculation until the solution is eventually revealed. On the other hand, it is the job of the composer to hide the solution so well, that it requires extreme creativity to find the answer. The reason I like to solve these difficult puzzles with only 2 moves is that on the one hand the solution is very much achievable, you only need to find 2 moves to win the game. The only sensible way to do that is 1.Qb4! which we can see is the solution: 1.Qb4! (zugzwang) Kxc7+/Kxa7+/Rxa7 2.bxa8=N#/b8=N#/Rc8#ĮDIT: Just noticed that /u/Rocky-64 said much the same thing here.I have recently become obsessed with solving very difficult checkmate in two puzzles. Ignoring that issue, here is my thought process: After 1.Kxc7+, we need to mate with 2.bxa8# somehow. So this problem is either an illegal position or is unsound, which is why it was ultimately disqualified. But now, after each of Black's three legal moves, White cannot mate in two (some retroanalysis directmates do use the convention that White should mate in two after Black's move if Black is to move). So it must be Black to move in this position. Black's only possible last move would have been Kc8-b8, but the king would have been in an impossible double-check beforehand. Namely, there is no way to reach this position with White to move. There's a big problem with this position. It would have won second prize, but was disqualified for a reason I'll get to in a moment. This problem was composed by Cyril Kipping, and entered into the Le Salut Public Miniature Tourney in 1929. The faulty mate-in-2 with the WQ on e1 was by Cyril Kipping, published in 1929. This pretty famous "trick" mate-in-1 problem was composed by Walter von Holzhausen in 1901. And since it is Black's turn, White indeed has a mate-in-1 against all possible black moves. However, this is a legitimate "trick" problem, because the solver should notice that the position is illegal with White to play (same reason as given above), and hence deduce it must be Black to move. By convention, White moves first in this type of composed problem, in which case there would be no solution. The earlier problem has the WQ on b4 (instead of e1) as the starting position, and the task is "mate in 1". Ironically, this problem was anticipated by a better composition that makes use of the position's retro-analytical aspect. Chess compositions have strict rules about legal positions, hence this one is considered invalid. For that reason, this mate-in-2 problem was stripped of the 2nd Prize it originally received. Specifically, the black king couldn't have just come from c8, where it would be in an impossible triple-check. The position is illegal with White to play, because none of Black's pieces could have made the last move. Please continue to give us your feedback and suggestions on how we can help make /r/chess better for everyone. Use the message the moderators link if your posts or comments don't appear, or for help with any administrative matters. Twitter/Facebook posts must contain a direct link to the tweet/post, and include the author's nameĬhess Spoiler format for problem answers etc., Instructions for /r/chess PGN addon ( Chrome, Firefox)ĭon’t engage in abusive, discriminatory, or bigoted behavior.ĭon't ask for advice about ongoing games.ĭo not use /r/chess exclusively to promote your own content. News Puzzles Games Strategy Twitch Other Resources
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